Using Point-Slope to Write Linear Equation[1]

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Shared by: Ben Stover
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Objective- To write a linear equation given a point and a slope. Write a linear equation in standard form given: slope = 3 m=3 y = mx + b y = 3x + -2 -3x -3x Not in standard form! y-intercept = -2 b = -2 -3x + y = -2 or Ax + By = C Where A, B and C are integers. 3x - y = 2 Write a linear equation in standard form given: slope = 2 y-intercept = 4 3 y = mx + b y= 2 x+4 - 2x 3 3 - 2 x 3 3 3 - 2 x + y = 4 3 - 2 x + y = 4 Not in standard form! Ax + By = C Where A, B and C are integers. No fractional coefficients! or - 2x + 3y = 12 2x - 3y = -12 Write a linear equation in standard form given: slope = -1 point = (2,4) 5 (x,y) 5 4 = -2 + b 5 + 2 + 2 5 5 5 y = mx + b y = -1 x + b 5 4 = -1 (2) + b y = -1 x + 22 5 5 + 1x 5 + 1x 5 5 1 x + y = 22 5 5 x + 5y = 22 4 2 = b = 22 5 Write a linear equation in standard form given: slope = -3 point = (1,-2) 7 (x,y) 7 3 -2 = -7 + b + 3 + 3 7 7 y = mx + b y = -3 x + b 7 -2 = -3 (1) + b y = -3 x + -11 7 7 + 3x 7 7 + 3x 7 7 7 3 x + y = -11 7 -14 + 3 = b = -11 7 7 7 -2 + 3 = b 3x + 7y = -11 Write a linear equation in standard form given: slope = 3 x-intercept = 4 5 (x,y) 5 0 = 3 (4) + b 5 0 = 12 + b 5 - 12 - 12 5 5 y = mx + b y= 3 x+b (4,0) y = 3 x + -12 5 5 3 x 5 5 - - 3x 5 5 5 -3 x + y = -12 0 +-12 = b = -12 5 -3x + 5y = -12 or 5 3x - 5y = 12 A hardware store sells extension ladders. A 16 ft. ladder costs $50 and the price increases $7.50 for each additional foot. If x = ladder length and y = price, write an equation for y in terms of x. Slope Change in price = $7.50/ ft. m = 7.50 y = mx + b y = 7.50x + b 50 = 7.5(16) + b 50 = 120 + b -120 -120 -70 = b Point 16 ft. cost $50 (x, y) = (16, 50) y = 7.5x - 70

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